Result is a 'sheet' of tetrahedra which is the basis for group name and physical properties.
What are the choices for charge compensation for the apical O ions?
At the same height as, and centered within the ring of 6 apical oxygens, is located an OH- ion, to create the lower surface of an octahedral sheet. (See Fig. 13.79 in the text - note the triangular facets.)
How many OH- are needed to finish an octahedral site layer ?
Thus: charge balance is accomplished
What are the likely octahedral cations? The usual suspects:
Substitution of Al for Si ? YES
Basic formula: [octahedral cation]6+ Si2O5 (OH)4
How is 6+ achieved with above list?
Hydrous minerals, low T formation, abundant elements (e.g., Mg, Al)
2+ and 3+ cations -> 6+ ??
SERPENTINE (lizardite, chrysotile, antigorite) Mg3Si2O5(OH)4
* Structural Modulation:
Note the layer stagger in the figures in the text (13.90, 13.91, 13.92)! - What does this mean for the symmetry ?
As above, both dioctahedral and trioctahedral versions!
Dioctahedral = PYROPHYLLITE Al2Si4O10(OH)2
Trioctahedral = TALC Mg3Si4O10(OH)2
K [...]6+ (Si3Al)O10 (OH)2
Dioctahedral = MUSCOVITE
Trioctahedral = BIOTITE
Also: Lepidolite: K (Li,Al) etc.
WHAT IF: INSERT A COMPLETE OCTAHEDRAL SHEET INTO INTERLAYER ?
Remember the simple brucite and gibbsite structures.
Dioctahedral and trioctahedral (and combinations of these) = chlorite
POLYTYPISM: Polytypes are structures that differ essentially only because essentially identical layers are stacked in different ways. 1M, 2M, 3T
INTERLAYERING - complex minerals
David Palmer (Technical information)